In the titration of the mixture of the strong base, OH- ions and the weaker base, CO32- ions, againstHCl, using the phenolphthalein indicator, the weaker base is first converted to_______
Question
In the titration of the mixture of the strong base, OH- ions and the weaker base, CO32- ions, againstHCl, using the phenolphthalein indicator, the weaker base is first converted to_______
Solution
In the titration of a mixture of a strong base (OH-) and a weaker base (CO32-) against HCl using phenolphthalein as an indicator, the weaker base (CO32-) is first converted to HCO3- (bicarbonate ion).
Here's the step-by-step process:
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The titration starts with the addition of HCl to the solution of OH- and CO32-.
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The strong base OH- reacts first with HCl because it is more reactive. The reaction is: OH- + HCl -> H2O + Cl-. This continues until all the OH- ions have reacted.
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After all the OH- ions have reacted, the HCl starts to react with the weaker base CO32-. The reaction is: CO32- + HCl -> HCO3- + Cl-.
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The bicarbonate ion (HCO3-) is the product of the reaction of the carbonate ion (CO32-) with HCl.
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The phenolphthalein indicator changes color, indicating the end point of the titration, which occurs when all the CO32- ions have been converted to HCO3-.
So, in this titration, the weaker base CO32- is first converted to HCO3-.
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