Martha pushes downward on a trunk with a force of 600 newtons. The force makes a thirty degree angle with the horizon and the trunk weighs 800 newtons. What is the normal force on the trunk

To solve this problem, we need to understand that the normal force is the force exerted by a surface that supports the weight of an object resting on it. It acts perpendicular (or normal) to the surface. The normal force can be calculated by balancing the forces acting on the trunk.

Here are the steps to solve this problem:

1. First, we need to calculate the vertical component of the force Martha is applying. This can be done using trigonometry. The vertical component (Fv) is equal to the force Martha applies (F) times the sine of the angle (θ) she is pushing at. So, Fv = F * sin(θ) = 600N * sin(30°) = 300N.

2. Next, we need to add this vertical component of the force to the weight of the trunk to find the total force acting downward. The weight of the trunk is given as 800N, so the total downward force (Fd) is Fd = Fv + weight = 300N + 800N = 1100N.

3. The normal force is the force that counteracts this total downward force. In this case, the normal force is equal to the total downward force, so the normal force is also 1100N.

So, the normal force on the trunk is 1100 newtons.