The drift velocity of electrons for a conductor connected in an electrical circuit is Vd. The conductor in now replaced by another conductor with same material and same length but double the area of cross section. The applied voltage remains same. The new drift velocity of electrons will be
Question
The drift velocity of electrons for a conductor connected in an electrical circuit is Vd. The conductor in now replaced by another conductor with same material and same length but double the area of cross section. The applied voltage remains same. The new drift velocity of electrons will be
Solution 1
To find the new drift velocity of electrons, we can use the equation:
Vd = (I / nAe)
Where: Vd is the drift velocity of electrons, I is the current flowing through the conductor, n is the number of charge carriers per unit volume, A is the cross-sectional area of the conductor, and e is the charge of an electron.
Since the material and length of the conductor remain the same, the number of charge carriers per unit volume (n) will also remain the same.
Now, let's consider the new conductor with double the area of cross section (2A). The current flowing through the conductor (I) remains the same, as the applied voltage remains the same.
Using the equation, we can rewrite it as:
Vd' = (I / n(2A)e)
Simplifying further, we get:
Vd' = (1/2) * Vd
Therefore, the new drift velocity of electrons (Vd') will be half of the original drift velocity (Vd).
Solution 2
To find the new drift velocity of electrons, we can use the equation:
Vd = (I / nAe)
Where: Vd is the drift velocity of electrons, I is the current flowing through the conductor, n is the number of charge carriers per unit volume, A is the cross-sectional area of the conductor, and e is the charge of an electron.
Since the material and length of the conductor remain the same, the number of charge carriers per unit volume (n) will also remain the same.
Now, let's consider the new conductor with double the area of cross section (2A). The current flowing through the conductor (I) remains the same, as the applied voltage remains the same.
Using the equation, we can rewrite it as:
Vd' = (I / n(2A)e)
Simplifying further, we get:
Vd' = (1/2) * Vd
Therefore, the new drift velocity of electrons (Vd') will be half of the original drift velocity (Vd).
Similar Questions
Suppose a electrical circuit uses 18 gauge wire and the drift velocity of electron through it wasvd = 0.15mm/s . Now the wire has been replaced by a 12 gauge copper wire which has twice thediameter of 18-gauge wire. If the current remains the same, what effect would this have on themagnitude of the drift velocity vdi) none— vd would be unchanged;ii) vd would be twice as great;iii) vd would be four times greater;iv) vd would be half as great;v) vd would be one-fourth as great.
How does the drift velocity change with a change in the potentialdifference across the conductor?
here is a current of 20 amperes in a copper wire of square metre area of cross-section. If the number of free electrons per cubic metre is then the drift velocity is:
Consider a conductor of length 0.5 m. A potential difference of 20V is applied across this conductor. If the drift velocity of electrons is given as 5.0 × 10-4ms-1, then determine the mobility of the electrons.
conductor of copper, the density of free electons is 5×10^23 electrons per unit volume, carrying current of intenisty 1.6A if the cross-sectional area of a conductor is 4mm^2 so the drift velocity of electrons is
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