What will be the output of the following python code? a = 0 def exp(): try: if(a == 0): return 1 except: return 0 res = exp() print(res) Options 1 0 None ValueError
Question
What will be the output of the following python code? a = 0
def exp(): try: if(a == 0): return 1 except: return 0 res = exp() print(res) Options 1 0 None ValueError
Solution
The output of the given Python code will be 1.
Here's the step by step explanation:
- The variable
ais initialized with the value 0. - The function
exp()is defined. Inside this function, atryblock is used. - Inside the
tryblock, there is a condition to check ifais equal to 0. Ifais 0, the function will return 1. - The
exceptblock will only execute if there is an error or exception in thetryblock. In this case, there is no error or exception, so theexceptblock is not executed. - The function
exp()is called and its return value is stored in the variableres. - The value of
resis printed, which is 1.
So, the correct option is 1.
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