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What will be the output of the following python code? a = 0 def exp(): try: if(a == 0): return 1 except: return 0 res = exp() print(res) Options 1 0 None ValueError

Question

What will be the output of the following python code? a = 0

def exp(): try: if(a == 0): return 1 except: return 0 res = exp() print(res) Options 1 0 None ValueError

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Solution

The output of the given Python code will be 1.

Here's the step by step explanation:

  1. The variable a is initialized with the value 0.
  2. The function exp() is defined. Inside this function, a try block is used.
  3. Inside the try block, there is a condition to check if a is equal to 0. If a is 0, the function will return 1.
  4. The except block will only execute if there is an error or exception in the try block. In this case, there is no error or exception, so the except block is not executed.
  5. The function exp() is called and its return value is stored in the variable res.
  6. The value of res is printed, which is 1.

So, the correct option is 1.

This problem has been solved

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