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A car with a weight of 15,000N is being towed up a 20 degree slope at constant velocity. Friction is negligible. What is the tension in the tow rope?Draw a free-body diagram to help you.Give your answer to 0 decimal places in N. Do not include the units in your answer i.e. you would write 12 N as 12

Question

A car with a weight of 15,000N is being towed up a 20 degree slope at constant velocity. Friction is negligible. What is the tension in the tow rope?Draw a free-body diagram to help you.Give your answer to 0 decimal places in N. Do not include the units in your answer i.e. you would write 12 N as 12

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Solution

To solve this problem, we need to understand that the tension in the tow rope must balance the component of the car's weight that acts parallel to the slope.

Here are the steps to solve this problem:

  1. Draw a free-body diagram: This is a sketch that shows all the forces acting on an object. In this case, the car. The forces acting on the car are its weight (which acts vertically downwards) and the tension in the tow rope (which acts along the slope).

  2. Resolve the weight into components: The weight of the car can be resolved into two components - one that acts perpendicular to the slope and one that acts parallel to the slope. The component of the weight that acts parallel to the slope is given by W*sin(θ), where W is the weight of the car and θ is the angle of the slope.

  3. Calculate the component of the weight that acts parallel to the slope: Substituting the given values into the formula, we get (15,000 N)*sin(20 degrees) = 5,142 N.

  4. Determine the tension in the tow rope: Since the car is moving at a constant velocity, the net force acting on it must be zero. This means that the tension in the tow rope must balance the component of the weight that acts parallel to the slope. Therefore, the tension in the tow rope is also 5,142 N.

So, the tension in the tow rope is 5142 N to 0 decimal places.

This problem has been solved

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