Knowee
Questions
Features
Study Tools

๐˜ผ ๐™˜๐™–๐™ง ๐™ฉ๐™ง๐™–๐™ซ๐™š๐™ก๐™จ ๐™–๐™ก๐™ค๐™ฃ๐™œ ๐™– ๐™จ๐™ฉ๐™ง๐™–๐™ž๐™œ๐™๐™ฉ ๐™ก๐™ž๐™ฃ๐™š ๐™–๐™ฉ ๐™– ๐™˜๐™ค๐™ฃ๐™จ๐™ฉ๐™–๐™ฃ๐™ฉ ๐™จ๐™ฅ๐™š๐™š๐™™ ๐™ค๐™› 60.0 ๐™ข๐™ž/๐™ ๐™›๐™ค๐™ง ๐™– ๐™™๐™ž๐™จ๐™ฉ๐™–๐™ฃ๐™˜๐™š ๐™™ ๐™–๐™ฃ๐™™ ๐™ฉ๐™๐™š๐™ฃ ๐™–๐™ฃ๐™ค๐™ฉ๐™๐™š๐™ง ๐™™๐™ž๐™จ๐™ฉ๐™–๐™ฃ๐™˜๐™š ๐™™ ๐™ž๐™ฃ ๐™ฉ๐™๐™š ๐™จ๐™–๐™ข๐™š ๐™™๐™ž๐™ง๐™š๐™˜๐™ฉ๐™ž๐™ค๐™ฃ ๐™–๐™ฉ ๐™–๐™ฃ๐™ค๐™ฉ๐™๐™š๐™ง ๐™˜๐™ค๐™ฃ๐™จ๐™ฉ๐™–๐™ฃ๐™ฉ ๐™จ๐™ฅ๐™š๐™š๐™™. ๐™๐™๐™š ๐™–๐™ซ๐™š๐™ง๐™–๐™œ๐™š ๐™ซ๐™š๐™ก๐™ค๐™˜๐™ž๐™ฉ๐™ฎ ๐™›๐™ค๐™ง ๐™ฉ๐™๐™š ๐™š๐™ฃ๐™ฉ๐™ž๐™ง๐™š ๐™ฉ๐™ง๐™ž๐™ฅ ๐™ž๐™จ 30.0 ๐™ข๐™ž/๐™. U๐™จ๐™š ๐™ฉ๐™๐™ž๐™จ ๐™ž๐™ฃ๐™›๐™ค๐™ง๐™ข๐™–๐™ฉ๐™ž๐™ค๐™ฃ ๐™ฉ๐™ค ๐™–๐™ฃ๐™จ๐™ฌ๐™š๐™ง 21-23 . What is the average speed for the new trip above?

Question

๐˜ผ ๐™˜๐™–๐™ง ๐™ฉ๐™ง๐™–๐™ซ๐™š๐™ก๐™จ ๐™–๐™ก๐™ค๐™ฃ๐™œ ๐™– ๐™จ๐™ฉ๐™ง๐™–๐™ž๐™œ๐™๐™ฉ ๐™ก๐™ž๐™ฃ๐™š ๐™–๐™ฉ ๐™– ๐™˜๐™ค๐™ฃ๐™จ๐™ฉ๐™–๐™ฃ๐™ฉ ๐™จ๐™ฅ๐™š๐™š๐™™ ๐™ค๐™› 60.0 ๐™ข๐™ž/๐™ ๐™›๐™ค๐™ง ๐™– ๐™™๐™ž๐™จ๐™ฉ๐™–๐™ฃ๐™˜๐™š ๐™™ ๐™–๐™ฃ๐™™ ๐™ฉ๐™๐™š๐™ฃ ๐™–๐™ฃ๐™ค๐™ฉ๐™๐™š๐™ง ๐™™๐™ž๐™จ๐™ฉ๐™–๐™ฃ๐™˜๐™š ๐™™ ๐™ž๐™ฃ ๐™ฉ๐™๐™š ๐™จ๐™–๐™ข๐™š ๐™™๐™ž๐™ง๐™š๐™˜๐™ฉ๐™ž๐™ค๐™ฃ ๐™–๐™ฉ ๐™–๐™ฃ๐™ค๐™ฉ๐™๐™š๐™ง ๐™˜๐™ค๐™ฃ๐™จ๐™ฉ๐™–๐™ฃ๐™ฉ ๐™จ๐™ฅ๐™š๐™š๐™™. ๐™๐™๐™š ๐™–๐™ซ๐™š๐™ง๐™–๐™œ๐™š ๐™ซ๐™š๐™ก๐™ค๐™˜๐™ž๐™ฉ๐™ฎ ๐™›๐™ค๐™ง ๐™ฉ๐™๐™š ๐™š๐™ฃ๐™ฉ๐™ž๐™ง๐™š ๐™ฉ๐™ง๐™ž๐™ฅ ๐™ž๐™จ 30.0 ๐™ข๐™ž/๐™. U๐™จ๐™š ๐™ฉ๐™๐™ž๐™จ ๐™ž๐™ฃ๐™›๐™ค๐™ง๐™ข๐™–๐™ฉ๐™ž๐™ค๐™ฃ ๐™ฉ๐™ค ๐™–๐™ฃ๐™จ๐™ฌ๐™š๐™ง 21-23 . What is the average speed for the new trip above?

...expand
๐Ÿง Not the exact question you are looking for?Go ask a question

Solution

The average speed for the entire trip is given as 30.0 mi/h. This is calculated by dividing the total distance travelled by the total time taken. In this case, the car travels the same distance 'd' twice, once at 60.0 mi/h and once at an unknown speed.

However, since the average speed of the entire trip is 30.0 mi/h, which is half of the speed of the first part of the trip, it suggests that the car spent the same amount of time travelling at 60.0 mi/h as it did at the unknown speed.

Therefore, the speed during the second part of the trip must also be 30.0 mi/h, because the average speed of 30.0 mi/h indicates that the total time spent is evenly split between travelling at 60.0 mi/h and the unknown speed.

So, the average speed for the new trip is 30.0 mi/h.

This problem has been solved

Similar Questions

๐˜ผ ๐™˜๐™–๐™ง ๐™ฉ๐™ง๐™–๐™ซ๐™š๐™ก๐™จ ๐™–๐™ก๐™ค๐™ฃ๐™œ ๐™– ๐™จ๐™ฉ๐™ง๐™–๐™ž๐™œ๐™๐™ฉ ๐™ก๐™ž๐™ฃ๐™š ๐™–๐™ฉ ๐™– ๐™˜๐™ค๐™ฃ๐™จ๐™ฉ๐™–๐™ฃ๐™ฉ ๐™จ๐™ฅ๐™š๐™š๐™™ ๐™ค๐™› 60.0 ๐™ข๐™ž/๐™ ๐™›๐™ค๐™ง ๐™– ๐™™๐™ž๐™จ๐™ฉ๐™–๐™ฃ๐™˜๐™š ๐™™ ๐™–๐™ฃ๐™™ ๐™ฉ๐™๐™š๐™ฃ ๐™–๐™ฃ๐™ค๐™ฉ๐™๐™š๐™ง ๐™™๐™ž๐™จ๐™ฉ๐™–๐™ฃ๐™˜๐™š ๐™™ ๐™ž๐™ฃ ๐™ฉ๐™๐™š ๐™จ๐™–๐™ข๐™š ๐™™๐™ž๐™ง๐™š๐™˜๐™ฉ๐™ž๐™ค๐™ฃ ๐™–๐™ฉ ๐™–๐™ฃ๐™ค๐™ฉ๐™๐™š๐™ง ๐™˜๐™ค๐™ฃ๐™จ๐™ฉ๐™–๐™ฃ๐™ฉ ๐™จ๐™ฅ๐™š๐™š๐™™. ๐™๐™๐™š ๐™–๐™ซ๐™š๐™ง๐™–๐™œ๐™š ๐™ซ๐™š๐™ก๐™ค๐™˜๐™ž๐™ฉ๐™ฎ ๐™›๐™ค๐™ง ๐™ฉ๐™๐™š ๐™š๐™ฃ๐™ฉ๐™ž๐™ง๐™š ๐™ฉ๐™ง๐™ž๐™ฅ ๐™ž๐™จ 30.0 ๐™ข๐™ž/๐™. U๐™จ๐™š ๐™ฉ๐™๐™ž๐™จ ๐™ž๐™ฃ๐™›๐™ค๐™ง๐™ข๐™–๐™ฉ๐™ž๐™ค๐™ฃ ๐™ฉ๐™ค ๐™–๐™ฃ๐™จ๐™ฌ๐™š๐™ง 21-23 21. What is the constant speed with which the car moved during the second distance ๐˜ฅ?

Anjali travels from her home to office at a speed of 40km/hr and returns from her office by increasing her speed by 50%. What is the average speed for her round journey?Choose the best optionClear Response30 km/hr60 km/hr72 km/hr48 km/hr

An auto travels at a rate of 25 km/h for 4 minutes, then at 50 km/h for 8 minutes, and finally at 20 km/h for 2 minutes. Find the average speed for the complete trip in meters per second. (Give the answer to one decimal place accuracy.)

A train travels 60 km at a speed of 30 km/h and another 120 km at a speed of 60 km/h. What is the average speed of the train for the entire journey?ย ย *40 km/h45 km/h50 km/h55 km/h

A bus travels up a hill at a constant speed of 40 km/h and returns down the hill at a constant speed of 60 km/h.ย  Calculate the average speed for the whole trip in m/s.

1/3

Upgrade your grade with Knowee

Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.