24. A particle is moving eastwards with a velocity of 5 m/s. In 10 seconds the velocity changes to 5m/s northwards. The average acceleration of the system in m/s2 is
Question
- A particle is moving eastwards with a velocity of 5 m/s. In 10 seconds the velocity changes to 5m/s northwards. The average acceleration of the system in m/s2 is
Solution
The average acceleration of a system is calculated by the change in velocity divided by the time it takes for this change to occur.
First, we need to find the change in velocity. The initial velocity is 5 m/s eastwards and the final velocity is 5 m/s northwards. Since these two velocities are perpendicular to each other, we can use Pythagoras' theorem to find the resultant or change in velocity.
Change in velocity = sqrt((final velocity)^2 + (initial velocity)^2) Change in velocity = sqrt((5 m/s)^2 + (5 m/s)^2) Change in velocity = sqrt(50) m/s Change in velocity = 7.07 m/s
Next, we divide this change in velocity by the time it takes for this change to occur to find the average acceleration.
Average acceleration = Change in velocity / time Average acceleration = 7.07 m/s / 10 s Average acceleration = 0.707 m/s^2
So, the average acceleration of the system is 0.707 m/s^2.
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