Wave X has the same frequency as wave Y. If wave X has twice the wavelength of Y, how does the speed of X compare to Y?A X has 1414 the speed of Y.B X has 1212 the speed of Y.C X has the same speed as Y.D X has twice the speed of Y.
Question
Wave X has the same frequency as wave Y. If wave X has twice the wavelength of Y, how does the speed of X compare to Y?A X has 1414 the speed of Y.B X has 1212 the speed of Y.C X has the same speed as Y.D X has twice the speed of Y.
Solution
The speed of a wave is given by the equation v = fλ, where v is the speed, f is the frequency, and λ is the wavelength.
Given that wave X and Y have the same frequency, we can write their speeds as:
v_X = f * λ_X and v_Y = f * λ_Y
The problem states that λ_X = 2 * λ_Y. We can substitute this into the equation for v_X:
v_X = f * 2 * λ_Y
Since v_Y = f * λ_Y, we can see that v_X = 2 * v_Y.
So, the speed of wave X is twice the speed of wave Y.
Therefore, the correct answer is D. X has twice the speed of Y.
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