You're writing a Bash script to process a list of filenames stored in a file, and for each file, you need to extract the base filename (without the path or extension). Which command correctly extracts the base filename for each line in the file?0.5 Markswhile read line; dofilename=$(basename "$line")echo "$filename"done < filenames.txtcat filenames.txt | xargs -I{} basename {} | echofind . -type f -exec basename {} \; | cat > filenames.txtfor line in $(cat filenames.txt); dofilename=$(basename $line)echo "$filename"donefor filename in $(cat filenames.txt); doecho "$(basename $filename)"done

Question

You're writing a Bash script to process a list of filenames stored in a file, and for each file, you need to extract the base filename (without the path or extension). Which command correctly extracts the base filename for each line in the file?0.5 Markswhile read line; dofilename= $(basename "$ line")echo " $filename"done < filenames.txtcat filenames.txt | xargs -I{} basename {} | echofind . -type f -exec basename {} \; | cat > filenames.txtfor line in$ (cat filenames.txt); dofilename= $(basename$ line)echo " $filename"donefor filename in$ (cat filenames.txt); doecho " $(basename$ filename)"done

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Solution

The correct command to extract the base filename for each line in the file is:

while read line; do
filename=$(basename "$line")
echo "$filename"
done < filenames.txt

This command reads each line from the file filenames.txt and assigns it to the variable line. The basename "$line" command extracts the base filename from the path, and this is assigned to the variable filename. The echo "$filename" command then prints the base filename. This process is repeated for each line in the file.

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