The number of required flip-flops to make a MOD-3 counter is:

To design a MOD-3 counter, you would need 2 flip-flops. Here's why:

1. A MOD-N counter requires enough flip-flops to represent N states. The number of states that can be represented by a flip-flop is 2^n, where n is the number of flip-flops.

2. So, to find the number of flip-flops needed, you need to solve the equation 2^n >= N. For a MOD-3 counter, this becomes 2^n >= 3.

3. If n=1, then 2^1 = 2, which is not enough to represent 3 states. But if n=2, then 2^2 = 4, which is enough.

4. Therefore, a MOD-3 counter requires 2 flip-flops.

To design a MOD-3 counter, you would need 2 flip-flops.

Here's why:

1. A MOD-N counter requires enough flip-flops to represent N states.

2. The number of states that can be represented by a flip-flop is 2^n, where n is the number of flip-flops.

3. To find the minimum number of flip-flops needed, you need to solve for n in the equation 2^n >= N.

4. For a MOD-3 counter, you would solve for n in the equation 2^n >= 3.

5. The smallest integer n that satisfies this equation is 2, because 2^2 = 4, which is greater than 3.

So, a MOD-3 counter requires 2 flip-flops.