The average weight of A, B and C is “45 mg”. If the average weight of A and B be “40 mg” and that of B and C be “43 mg”, then the weight of B is:
Question
The average weight of A, B and C is “45 mg”. If the average weight of A and B be “40 mg” and that of B and C be “43 mg”, then the weight of B is:
Solution
Let's solve this step by step:
Step 1: We know that the average weight of A, B, and C is 45 mg. So, the total weight of A, B, and C is 3*45 = 135 mg.
Step 2: The average weight of A and B is 40 mg. So, the total weight of A and B is 2*40 = 80 mg.
Step 3: The average weight of B and C is 43 mg. So, the total weight of B and C is 2*43 = 86 mg.
Step 4: If we add the total weights of A and B and B and C, we get 80 mg + 86 mg = 166 mg. This is the total weight of A, B, B, and C.
Step 5: Since we know that the total weight of A, B, and C is 135 mg, we can subtract this from the total weight of A, B, B, and C to find the weight of B. So, B weighs 166 mg - 135 mg = 31 mg.
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