Geometry of 2D shapesCLASSIFYING QUADRILATERALSIn quadrilateral PQRS𝑃𝑄𝑅𝑆 below, P^=49°𝑃^=49°, Q^=x𝑄^=𝑥, R^=41°𝑅^=41°, and S^=46°𝑆^=46°.Determine the size of x𝑥, giving a reason for your answer.Answer:x=𝑥= °°
Question
Geometry of 2D shapesCLASSIFYING QUADRILATERALSIn quadrilateral PQRS𝑃𝑄𝑅𝑆 below, P^=49°𝑃^=49°, Q^=x𝑄^=𝑥, R^=41°𝑅^=41°, and S^=46°𝑆^=46°.Determine the size of x𝑥, giving a reason for your answer.Answer:x=𝑥= °°
Solution
To find the value of x, we need to know that the sum of the interior angles of a quadrilateral is 360 degrees.
Given that P = 49°, R = 41°, and S = 46°, we can find the value of Q (x) by subtracting the sum of P, R, and S from 360.
So, x = 360° - (49° + 41° + 46°)
First, add the given angles: 49° + 41° + 46° = 136°
Then subtract this sum from 360°: x = 360° - 136° = 224°
So, the measure of angle Q (x) is 224 degrees.
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