Estimate the value x to balance the given equation.Mg3N2 (aq)+xH2O (l)→3Mg(OH)2 (aq)+2NH3 (g)

To balance the equation, we need to ensure that the number of atoms for each element is the same on both sides of the equation.

The equation is: Mg3N2 (aq) + xH2O (l) → 3Mg(OH)2 (aq) + 2NH3 (g)

1. First, let's balance the Mg (Magnesium) atoms. There are 3 Mg atoms on both sides, so no changes are needed here.

2. Next, let's balance the N (Nitrogen) atoms. There are 2 N atoms on the left side and 2 on the right side (in 2NH3), so no changes are needed here either.

3. Now, let's balance the O (Oxygen) atoms. There are 2x O atoms on the left side (in xH2O) and 6 on the right side (in 3Mg(OH)2). To balance this, we need x to be 3, so that there are 6 O atoms on both sides.

4. Finally, let's balance the H (Hydrogen) atoms. There are 2x H atoms on the left side (in xH2O) and 12 on the right side (6 in 3Mg(OH)2 and 6 in 2NH3). With x being 3, we have 6 H atoms on the left side, which is not balanced. To balance this, we need x to be 6, so that there are 12 H atoms on both sides.

So, the balanced equation is: Mg3N2 (aq) + 6H2O (l) → 3Mg(OH)2 (aq) + 2NH3 (g)

Therefore, the value of x that balances the equation is 6.