Knowee
Questions
Features
Study Tools

An element X has four naturally occurring isotopes, with natural abundances and masses outlined in the table below. Mass (a.m.u) Natural Abundance (%)21.00 45.50 %23.00 32.00 %24.00 12.60 %26.00 9.90 %Calculate the atomic mass of element X, to two decimal places.

Question

An element X has four naturally occurring isotopes, with natural abundances and masses outlined in the table below. Mass (a.m.u) Natural Abundance (%)21.00 45.50 %23.00 32.00 %24.00 12.60 %26.00 9.90 %Calculate the atomic mass of element X, to two decimal places.

🧐 Not the exact question you are looking for?Go ask a question

Solution

The atomic mass of an element is calculated by multiplying the mass of each isotope by its natural abundance (expressed as a decimal), and then adding these values together.

Here's how to do it for element X:

  1. For the isotope with a mass of 21.00 a.m.u, multiply 21.00 by 45.50% (or 0.4550 in decimal form). This gives you 9.5550.

  2. For the isotope with a mass of 23.00 a.m.u, multiply 23.00 by 32.00% (or 0.3200 in decimal form). This gives you 7.3600.

  3. For the isotope with a mass of 24.00 a.m.u, multiply 24.00 by 12.60% (or 0.1260 in decimal form). This gives you 3.0240.

  4. For the isotope with a mass of 26.00 a.m.u, multiply 26.00 by 9.90% (or 0.0990 in decimal form). This gives you 2.5740.

  5. Add these four values together: 9.5550 + 7.3600 + 3.0240 + 2.5740 = 22.5130.

So, the atomic mass of element X is 22.51 a.m.u (rounded to two decimal places).

This problem has been solved

Similar Questions

A fictional element has two naturally occurring isotopes with the natural abundances shown here: ATOMIC MASS (AMU) ABUNDANCE1650.0%1850.0% Which statement is TRUE for this element?Group of answer choicesThe atomic mass would be 16.The atomic mass would be less than 16.The atomic mass would be 18.The atomic mass would be more than 18.The atomic mass would be 17.

lement X has two isotopes. Their mass numbers are 69 and 71 The percentage abundance of each isotope is: • 60% of 69 X • 40% of 71 X Estimate the relative atomic mass of element X. [1 mark] Tick one box. < 69.5 Between 69.5 and 70.0 Between 70.0 and 70.5 > 70.5

A fictional element named Schwartzium is found to have two naturally occurring isotopes with the natural abundances shown here:          Mass (amu)         % Abundance           32.3456                   65%           31.7812                   35% The calculated atomic mass (in amu) of Schwartzium is (place only a numerical answer, no units, in the following box):Group of answer choices32.3456 amu31.7812 amu31.9787 amu32.1481 amuinsufficient information provided to answer question

The Atomic  of an element indicates the average mass number for an atom and its isotopes and will therefore include one or more  places.

Define the terms mass number (A), atomic number (Z) and isotopes of an element

1/3

Upgrade your grade with Knowee

Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.