The vertex of a parabola given by the equation f(x) = ax^2 + bx + c is given by the point (-b/2a, f(-b/2a)).

In the given equation f(x) = x^2 + 3x + 2, a = 1 and b = 3.

So, the x-coordinate of the vertex is -b/2a = -3/(2*1) = -1.5.

Substitute x = -1.5 into the equation to find the y-coordinate of the vertex:

f(-1.5) = (-1.5)^2 + 3*(-1.5) + 2 = 2.25 - 4.5 + 2 = -0.25.

So, the vertex of the parabola is (-1.5, -0.25).

Question

The vertex of a parabola given by the equation f(x) = ax^2 + bx + c is given by the point (-b/2a, f(-b/2a)).

In the given equation f(x) = x^2 + 3x + 2, a = 1 and b = 3.

So, the x-coordinate of the vertex is -b/2a = -3/(2*1) = -1.5.

Substitute x = -1.5 into the equation to find the y-coordinate of the vertex:

f(-1.5) = (-1.5)^2 + 3*(-1.5) + 2 = 2.25 - 4.5 + 2 = -0.25.

So, the vertex of the parabola is (-1.5, -0.25).

Knowee AI · Accepted Answer

The vertex of a parabola given by the equation f(x) = ax^2 + bx + c is given by the point (-b/2a, f(-b/2a)).

In the given equation f(x) = x^2 + 3x + 2, a = 1 and b = 3.

So, the x-coordinate of the vertex is -b/2a = -3/(2*1) = -1.5.

Substitute x = -1.5 into the equation to find the y-coordinate of the vertex:

f(-1.5) = (-1.5)^2 + 3*(-1.5) + 2 = 2.25 - 4.5 + 2 = -0.25.

So, the vertex of the parabola is (-1.5, -0.25).

What is the vertex of f(x) = x2 + 3x + 2?