The correct answer is A. A complete graph 𝐾𝑛 has 𝑛(𝑛−1)/2 edges.

Here's why:

A complete graph is a simple undirected graph in which every pair of distinct vertices is connected by a unique edge.

In a complete graph, every vertex is connected to every other vertex. So, for a graph with 'n' vertices, each vertex is connected to 'n-1' other vertices.

However, this counts each edge twice (once for each vertex it connects), so we must divide by 2 to get the correct number of edges.

Therefore, a complete graph 𝐾𝑛 has 𝑛(𝑛−1)/2 edges.

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The correct answer is A. A complete graph 𝐾𝑛 has 𝑛(𝑛−1)/2 edges.

Here's why:

A complete graph is a simple undirected graph in which every pair of distinct vertices is connected by a unique edge.

In a complete graph, every vertex is connected to every other vertex. So, for a graph with 'n' vertices, each vertex is connected to 'n-1' other vertices.

However, this counts each edge twice (once for each vertex it connects), so we must divide by 2 to get the correct number of edges.

Therefore, a complete graph 𝐾𝑛 has 𝑛(𝑛−1)/2 edges.

Knowee AI · Accepted Answer

The correct answer is A. A complete graph 𝐾𝑛 has 𝑛(𝑛−1)/2 edges.

Here's why:

A complete graph is a simple undirected graph in which every pair of distinct vertices is connected by a unique edge.

In a complete graph, every vertex is connected to every other vertex. So, for a graph with 'n' vertices, each vertex is connected to 'n-1' other vertices.

However, this counts each edge twice (once for each vertex it connects), so we must divide by 2 to get the correct number of edges.

Therefore, a complete graph 𝐾𝑛 has 𝑛(𝑛−1)/2 edges.

Which of the following is true for a complete graph 𝐾𝑛K n ?A. It has 𝑛(𝑛−1)/2n(n−1)/2 edges.B. It has 𝑛n edges.C. It has 𝑛−1n−1 edges.D. It has 𝑛(𝑛+1)/2n(n+1)/2 edges.

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Which of the following is true for a complete graph 𝐾𝑛K n​ ?A. It has 𝑛(𝑛−1)/2n(n−1)/2 edges.B. It has 𝑛n edges.C. It has 𝑛−1n−1 edges.D. It has 𝑛(𝑛+1)/2n(n+1)/2 edges.

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Which of the following is true for a complete graph 𝐾𝑛K n ?A. It has 𝑛(𝑛−1)/2n(n−1)/2 edges.B. It has 𝑛n edges.C. It has 𝑛−1n−1 edges.D. It has 𝑛(𝑛+1)/2n(n+1)/2 edges.