wo salesmen A and B together sold 30 pens. A sold all his pens at the same rate, so does B. Though A sold his pens at a different rate than at a rate B sold, they both received the same amount after selling all their pens. If A had sold his pens at the rate at which B sold, he would have received Rs.320. If B had sold his pens at the rate at which A sold, he would have received Rs.245. At what price did B sell each of his pens?Enter your response (as an integer) using the virtual keyboard in the box provided below.

The problem can be solved using the system of linear equations.

Let's denote:

• the number of pens sold by A as a,
• the number of pens sold by B as b,
• the price per pen sold by A as x,
• the price per pen sold by B as y.

From the problem, we know that:

1. a + b = 30 (A and B together sold 30 pens)
2. ax = by (A and B received the same amount after selling all their pens)
3. ay = 320 (If A had sold his pens at the rate at which B sold, he would have received Rs.320)
4. bx = 245 (If B had sold his pens at the rate at which A sold, he would have received Rs.245)

From equation 3) we can express a as a = 320/y.

Substitute a from equation 3) into equation 1) to get b = 30 - 320/y.

Substitute b from equation 4) into equation 2) to get x = 245/(30 - 320/y).

Now we have two equations with two variables (x and y) which can be solved simultaneously.

From equation 2) we can express x as x = by/a. Substitute x into the equation from step 4) to get y = sqrt(320*245/30) = 10.

So, B sold each of his pens for Rs.10.