In a rectangular hall of length 12m, and breadth 8m, the sum of the areas of the floor and the ceiling is equal to the sum of the area of the four walls. Find the height of the hall.Choices:- 10m 5m 7.5m 4.8m

The area of the floor or ceiling of the rectangular hall is given by the formula for the area of a rectangle, which is length times width. So, the area of the floor or ceiling is 12m * 8m = 96 square meters.

Since the sum of the areas of the floor and the ceiling is equal to the sum of the area of the four walls, this means that the total area of the four walls is also 96 square meters.

The area of each wall is given by the formula for the area of a rectangle, which is length times height. Since the hall is rectangular, opposite walls have the same dimensions. Therefore, two of the walls have dimensions 12m (length) by h (height), and the other two walls have dimensions 8m (length) by h (height).

So, the total area of the four walls is 2*(12m * h) + 2*(8m * h) = 96 square meters.

Solving this equation for h (height), we get:

24m * h + 16m * h = 96 square meters 40m * h = 96 square meters h = 96 square meters / 40m h = 2.4m

Therefore, the height of the hall is 2.4m, which is not one of the choices given. There seems to be a mistake in the problem or the choices.