A person covers a certain distance with certain speed if he increases his speed by 15 km/hr. Then he will be 16 min. early. By how much time he will be late if he reduces his speed by 12 km/hr, if his initial speed is 60 km/hr?
Question
A person covers a certain distance with certain speed if he increases his speed by 15 km/hr. Then he will be 16 min. early. By how much time he will be late if he reduces his speed by 12 km/hr, if his initial speed is 60 km/hr?
Solution
To solve this problem, we need to use the concept of relative speed and time.
Step 1: Convert the time difference to hours 16 minutes = 16/60 = 0.267 hours
Step 2: Calculate the distance We know that time = distance/speed. So, we can find the distance by multiplying the speed difference by the time difference. Distance = (60+15) km/hr * 0.267 hr = 20 km
Step 3: Calculate the new time If the person reduces his speed by 12 km/hr, his new speed will be 60-12 = 48 km/hr. We can find the new time by dividing the distance by the new speed. Time = 20 km / 48 km/hr = 0.417 hours
Step 4: Convert the time to minutes 0.417 hours = 0.417*60 = 25 minutes
Step 5: Calculate the difference in time The person will be late by 25 - 16 = 9 minutes if he reduces his speed by 12 km/hr.
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