for the equation: (y - 2)2 = 8(x - 5); identify focusQuestion 9Select one:(0 , 0)(2 , 5)(2 , 8)(7 , 2)Clear my choice◄ weekend sheet t3 w8Jump to...
Question
for the equation: (y - 2)2 = 8(x - 5); identify focusQuestion 9Select one:(0 , 0)(2 , 5)(2 , 8)(7 , 2)Clear my choice◄ weekend sheet t3 w8Jump to...
Solution
The given equation is in the form of a parabola equation (y - k)² = 4a(x - h), where (h, k) is the vertex of the parabola and 'a' is the distance from the vertex to the focus.
In the given equation, (y - 2)² = 8(x - 5), we can see that h = 5, k = 2 and 4a = 8.
So, a = 8/4 = 2.
The focus of a parabola that opens rightward (as this one does, because the y-term is squared) is given by the point (h + a, k).
Substituting the values we have, the focus is at (5 + 2, 2) = (7, 2).
So, the focus of the given parabola is (7, 2).
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