15. The Autorikshaw fare in a city is charged Rs 10 for the first kilometer and @ Rs 4 per kilometer for subsequent distance covered. Write the linear equation to express the above statement. Draw the graph of the linear equation.
Question
- The Autorikshaw fare in a city is charged Rs 10 for the first kilometer and @ Rs 4 per kilometer for subsequent distance covered. Write the linear equation to express the above statement. Draw the graph of the linear equation.
Solution
The linear equation for the given situation can be written as follows:
Let's denote:
- x as the total distance covered in kilometers (with x > 1, because the first kilometer has a different cost)
- y as the total fare in Rs.
According to the problem, the fare for the first kilometer is Rs 10 and for the subsequent kilometers, the fare is Rs 4 per kilometer. So, for x kilometers, the fare would be Rs 10 for the first kilometer and Rs 4 for each of the remaining (x-1) kilometers.
So, the total fare y can be calculated as:
y = 10 + 4*(x-1)
This is the linear equation representing the autorickshaw fare.
To draw the graph of this linear equation, you would typically:
-
Draw a set of axes, labeling the x-axis as "Distance in kilometers" and the y-axis as "Fare in Rs".
-
Plot the y-intercept, which in this case is (0,10).
-
Use the slope of the line (which is 4, the rate at which the fare increases for each additional kilometer after the first) to find another point on the line. For example, when x=2 (i.e., a total distance of 2 kilometers), y = 10 + 4*(2-1) = 14. So, you would plot the point (2,14).
-
Draw a line through the points you've plotted.
Remember that this line only applies for x > 1, because the fare structure is
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