The total number of electrons in sulphur with azimuthal quantum number I = 1 are:

To determine the total number of electrons in sulfur with azimuthal quantum number $l = 1$, follow these steps:

1. Identify the atomic number of sulfur: Sulfur has an atomic number of 16, which means it has 16 electrons.

2. Understand the azimuthal quantum number $l$: The azimuthal quantum number $l$ corresponds to the subshells. For $l = 1$, this represents the p-subshell.

3. Determine the electron configuration of sulfur: The electron configuration of sulfur is: $1s^2 \, 2s^2 \, 2p^6 \, 3s^2 \, 3p^4$

4. Identify the electrons in the p-subshells: The p-subshells are those with $l = 1$. From the electron configuration:

   • $2p^6$ has 6 electrons.
   • $3p^4$ has 4 electrons.

5. Sum the electrons in the p-subshells: $6 \, (from \, 2p^6) + 4 \, (from \, 3p^4) = 10$

Therefore, the total number of electrons in sulfur with azimuthal quantum number $l = 1$ is 10.