Which equation represents the reaction for which the enthalpy change, ∆H, is the meanbond enthalpy of the C–H bond?A ¼CH 4(g) → ¼C(g) + H(g)B CH 4(g) → C(s) + 2H 2 (g)C CH 4(g) → C(g) + 4H(g)D CH 4(g) → C(g) + 2H2 (g)
Question
Which equation represents the reaction for which the enthalpy change, ∆H, is the meanbond enthalpy of the C–H bond?A ¼CH 4(g) → ¼C(g) + H(g)B CH 4(g) → C(s) + 2H 2 (g)C CH 4(g) → C(g) + 4H(g)D CH 4(g) → C(g) + 2H2 (g)
Solution
The correct answer is A.
The mean bond enthalpy refers to the energy needed to break a specific type of bond in one mole of gaseous molecules. In this case, we are looking for the equation that represents the breaking of a C-H bond.
Option A, ¼CH4(g) → ¼C(g) + H(g), represents the breaking of one C-H bond in methane (CH4). The coefficients are divided by 4 to represent the breaking of just one of the four identical bonds in a methane molecule.
The other options (B, C, D) represent the breaking of more than one C-H bond or the formation of new bonds, which is not what we are looking for in this case.
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