Solve the equation 9x 2 = 11 + 6x using the quadratic formula.Question 4Select one:a.x=−1+123√3𝑥=−1+1233 and x=−1−123√3𝑥=−1−1233b.x=13𝑥=13 and x=113𝑥=113c.x=1+23√3𝑥=1+233 and x=1−23√3𝑥=1−233d.No Real Solutions

The given equation is 9x^2 = 11 + 6x.

First, we need to rearrange the equation into standard quadratic form ax^2 + bx + c = 0.

Subtract 11 and 6x from both sides to get:

9x^2 - 6x - 11 = 0

Now we can use the quadratic formula, which is x = [-b ± sqrt(b^2 - 4ac)] / (2a), where a, b, and c are the coefficients from the quadratic equation.

In this case, a = 9, b = -6, and c = -11.

Substitute these values into the quadratic formula:

x = [6 ± sqrt((-6)^2 - 49(-11))] / (2*9) x = [6 ± sqrt(36 + 396)] / 18 x = [6 ± sqrt(432)] / 18 x = [6 ± 6√3] / 18 x = 1/3 ± √3/3

So the solutions are x = 1/3 + √3/3 and x = 1/3 - √3/3.

Therefore, the correct answer is c. x=1+23√3 and x=1−23√3.