Which reaction shows that the enthalpy of formation of CS2 is Hf = 89.4 kJ/mol?A.C(s) + 2S(s) + 89.4 kJ CS2(l)B.C(s) + 2S(s) + 89.4 kJ CS2(l) + 89.4 kJC.C(s) + 2S(s) CS2(l)D.C(s) + 2S(s) CS2(l) + 89.4 kJSUBMITarrow_backPREVIOUS
Question
Which reaction shows that the enthalpy of formation of CS2 is Hf = 89.4 kJ/mol?A.C(s) + 2S(s) + 89.4 kJ CS2(l)B.C(s) + 2S(s) + 89.4 kJ CS2(l) + 89.4 kJC.C(s) + 2S(s) CS2(l)D.C(s) + 2S(s) CS2(l) + 89.4 kJSUBMITarrow_backPREVIOUS
Solution
The correct reaction that shows the enthalpy of formation of CS2 is Hf = 89.4 kJ/mol is C.
C(s) + 2S(s) → CS2(l)
This is because the enthalpy of formation (ΔHf) is defined as the heat change that results when one mole of a compound is formed from its elements at their standard states. In this case, one mole of CS2 is formed from its elements, Carbon (C) and Sulfur (S), in their standard states. The heat change associated with this reaction is the enthalpy of formation, which is given as 89.4 kJ/mol. The other options involve additional energy terms which are not part of the standard definition of enthalpy of formation.
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