A box weighing 64.0 NN rests on a table. A rope tied to the box runs vertically upward over a pulley and a weight is hung from the other end.Figure1 of 1Part ADetermine the force that the table exerts on the box if the weight hanging on the other side of the pulley weighs 30.0 NN .
Question
A box weighing 64.0 NN rests on a table. A rope tied to the box runs vertically upward over a pulley and a weight is hung from the other end.Figure1 of 1Part ADetermine the force that the table exerts on the box if the weight hanging on the other side of the pulley weighs 30.0 NN .
Solution
The force that the table exerts on the box is the sum of the weight of the box and the upward force exerted by the weight on the other side of the pulley.
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The weight of the box is given as 64.0 N. This force is acting downwards.
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The weight on the other side of the pulley is given as 30.0 N. This force is acting upwards.
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Since these forces are acting in opposite directions, we subtract the upward force from the downward force to find the net force acting on the box.
So, 64.0 N (downwards) - 30.0 N (upwards) = 34.0 N (downwards)
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The force that the table exerts on the box must balance this net force to keep the box in equilibrium (not accelerating).
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Therefore, the force that the table exerts on the box is 34.0 N, acting upwards.
Similar Questions
Determine the force that the table exerts on the box if the weight hanging on the other side of the pulley weighs 88.0 NN .
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