Java Regex Finder Example
Solution
Sure, here is a simple example of using Java Regex (Regular Expressions) to find a pattern in a string:
import java.util.regex.Matcher;
import java.util.regex.Pattern;
public class Main {
public static void main(String[] args) {
// Input string to be searched
String text = "This is a sample text that contains [email protected]";
// Define regex pattern
String patternString = "[a-zA-Z0-9._%-]+@[a-zA-Z0-9.-]+\\.[a-zA-Z]{2,4}";
// Compile regex pattern
Pattern pattern = Pattern.compile(patternString);
// Create matcher object
Matcher matcher = pattern.matcher(text);
// Find matches
while (matcher.find()) {
// Print the matched text and its starting position
System.out.println("Found match: " + matcher.group() + " at position " + matcher.start());
}
}
}
In this example, we are searching for an email address in the input string. The regex pattern [a-zA-Z0-9._%-]+@[a-zA-Z0-9.-]+\\.[a-zA-Z]{2,4} is used to match any email address. The Pattern.compile() method is used to compile the regular expression into a Pattern object. The matcher() method is then used to create a Matcher object from the Pattern object. The find() method of the Matcher object is used in a loop to find all matches in the input string. For each match, we print the matched text and its starting position in the input string.
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