Find the limit. Use l'Hospital's Rule if appropriate. If there is a more elementary method, consider using it.lim x→0+ (cos(x))7/x2
Question
Find the limit. Use l'Hospital's Rule if appropriate. If there is a more elementary method, consider using it.lim x→0+ (cos(x))7/x2
Solution
To find the limit of the function as x approaches 0 from the right, we can use l'Hospital's Rule. However, before we can apply l'Hospital's Rule, we need to rewrite the function in a form that allows us to use the rule. l'Hospital's Rule can be used when the limit of a function is in the form of 0/0 or ∞/∞.
The given function is (cos(x))^7 / x^2. As x approaches 0, cos(x) approaches 1, so the numerator approaches 1. The denominator approaches 0 as x approaches 0. So, the function is not in the form that allows us to use l'Hospital's Rule directly.
However, we can rewrite the function as 7(cos(x) - 1) / x^2. Now, as x approaches 0, both the numerator and the denominator approach 0, so we can apply l'Hospital's Rule.
The derivative of the numerator, using the chain rule, is -7sin(x). The derivative of the denominator is 2x. So, the limit of the function as x approaches 0 is the limit of the ratio of these derivatives as x approaches 0.
lim x→0+ -7sin(x) / 2x
We can apply l'Hospital's Rule again, because this limit is still in the form of 0/0. The derivative of -7sin(x) is -7cos(x), and the derivative of 2x is 2.
So, the limit of the function as x approaches 0 is the limit of the ratio of these derivatives as x approaches 0.
lim x→0+ -7cos(x) / 2
As x approaches 0, cos(x) approaches 1, so the limit is -7/2.
So, the limit of the original function as x approaches 0 from the right is -7/2.
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