ccording to Shannon Hartley theorem,a.the channel capacity becomes infinite with infinite bandwidthb.Both b) and c) are correctc.the channel capacity does not become infinite with infinite bandwidthd.Has a tradeoff between bandwidth and Signal to noise ratio

The Shannon-Hartley theorem states that the channel capacity (C) of a communication channel is proportional to the bandwidth (B) and the logarithm of the signal-to-noise ratio (S/N). The formula is given as:

C = B log2(1 + S/N)

Now, let's analyze the options:

a. The channel capacity becomes infinite with infinite bandwidth: This is not entirely correct. While it's true that the channel capacity increases with the bandwidth, it doesn't become infinite with infinite bandwidth because the capacity also depends on the signal-to-noise ratio.

b. Both b) and c) are correct: This option cannot be evaluated as it refers to itself and option c).

c. The channel capacity does not become infinite with infinite bandwidth: This is correct for the reasons explained in option a).

d. Has a tradeoff between bandwidth and Signal to noise ratio: This is also correct. The Shannon-Hartley theorem shows that there is a tradeoff between bandwidth and signal-to-noise ratio in determining the channel capacity. If the signal-to-noise ratio is high, a lower bandwidth might be sufficient to achieve a certain channel capacity. Conversely, if the signal-to-noise ratio is low, a higher bandwidth might be needed to achieve the same channel capacity.

So, the correct answers are c) and d).