[Fe(CN)6]3– should be an inner orbital complex. Ignoring the pairing energy, the value of crystal field stabilization energy for this complex is (-) _______ Δ
Question
[Fe(CN)6]3– should be an inner orbital complex. Ignoring the pairing energy, the value of crystal field stabilization energy for this complex is (-) _______ Δ
Solution
The complex [Fe(CN)6]3– is indeed an inner orbital or low spin complex. This is because CN- is a strong field ligand and it causes the pairing of electrons in the 3d orbitals of Fe.
The Fe in [Fe(CN)6]3– is in the +3 oxidation state. Therefore, it has 5 electrons in the 3d orbitals.
In an inner orbital or low spin complex, the electrons are first paired up in the lower energy d orbitals before occupying the higher energy ones. Therefore, in [Fe(CN)6]3–, all 5 electrons are paired up in the t2g orbitals, and the eg orbitals are empty.
The crystal field stabilization energy (CFSE) for an inner orbital complex is calculated as follows:
CFSE = -0.4n(Delta) + 0.6P
where n is the number of electrons in the t2g orbitals, Delta is the crystal field splitting energy, and P is the pairing energy.
Ignoring the pairing energy (P = 0), the CFSE for [Fe(CN)6]3– is:
CFSE = -0.4*5(Delta) = -2 Delta
So, the value of crystal field stabilization energy for this complex is -2 Delta.
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