In a Shapiro-Wilk Test for Normality associated with a t-test performed, the p-value for group A is 0.054, while the p-value for group B is 0.15. Which of the following is true?Group of answer choicesThe normality assumption is met.The normality assumption is not met.Not enough information to conclude about normalityNo answer text provided.

When conducting a hypothesis test about p we can assume the test statistic Z=P̂ −pp(1−p)n√𝑍=𝑃^−𝑝𝑝(1−𝑝)𝑛 approximately follows a standard normal distribution if:Question 5Select one:a.the data is normally distributedb.the data is continuousc.np≥5 or n(1−p)≥5𝑛𝑝≥5 or 𝑛(1−𝑝)≥5 d.np≥5 and n(1−p)≥5

Is the normality condition satisfied?Based on the Answer, as we Answer observe Answer, we can say that the condition of normality is Answer.

In testing the hypothesesH0: μ = 50HA: μ < 50we found that the standardised test statistic is Z = –1.59. Calculate the p-value.Group of answer choices0.02950.05590.11180.9441

Which test could you use instead of the repeated measures t-test, if the Shapiro-Wilk test indicates that your data is not normally distributed?Question 5Answera.Levene's testb.The Wilcoxon testc.An independent-sample t-test as it is suitable for two separate groups of participantsd.The Mann-Whitney U test

Suppose you conduct a t test on mean of Normal population: 𝐻0:𝜇=100 vs 𝐻1:𝜇>100. If sample size is 15 and test statistic t0 = 0.89, then using t table the P-value range is found to be