Here is a Python solution for the problem:

```python
def largest_subset(nums):
if not nums: return []
nums.sort()
dp = [[num] for num in nums]
for i in range(len(nums)):
for j in range(i):
if nums[i] % nums[j] == 0 and len(dp[i])

Question

Here is a Python solution for the problem:

```python
def largest_subset(nums):
    if not nums: return []
    nums.sort()
    dp = [[num] for num in nums]
    for i in range(len(nums)):
        for j in range(i):
            if nums[i] % nums[j] == 0 and len(dp[i]) < len(dp[j]) + 1:
                dp[i] = dp[j] + [nums[i]]
    return max(dp, key=len)

print(largest_subset([3, 5, 10, 20, 21]))  # Output: [5, 10, 20]
print(largest_subset([1, 3, 6, 24]))  # Output: [1, 3, 6, 24]
```

Here is a step-by-step explanation of the code:

1. If the input list `nums` is empty, return an empty list.
2. Sort the list `nums` in ascending order.
3. Initialize a list `dp` where each element is a list containing one element from `nums`. This list will be used to store the largest subsets that satisfy the condition for each element in `nums`.
4. Iterate over each element in `nums` with index `i`.
5. For each `i`, iterate over each element with index `j` that comes before `i`.
6. If `nums[i]` is divisible by `nums[j]` and the length of the subset at `dp[i]` is less than the length of the subset at `dp[j]` plus one, update `dp[i]` to be the subset at `dp[j]` plus `nums[i]`.
7. After iterating over all elements in `nums`, find and return the longest subset in `dp`.

Knowee AI · Accepted Answer

Here is a Python solution for the problem:

```python
def largest_subset(nums):
    if not nums: return []
    nums.sort()
    dp = [[num] for num in nums]
    for i in range(len(nums)):
        for j in range(i):
            if nums[i] % nums[j] == 0 and len(dp[i]) < len(dp[j]) + 1:
                dp[i] = dp[j] + [nums[i]]
    return max(dp, key=len)

print(largest_subset([3, 5, 10, 20, 21]))  # Output: [5, 10, 20]
print(largest_subset([1, 3, 6, 24]))  # Output: [1, 3, 6, 24]
```

Here is a step-by-step explanation of the code:

1. If the input list `nums` is empty, return an empty list.
2. Sort the list `nums` in ascending order.
3. Initialize a list `dp` where each element is a list containing one element from `nums`. This list will be used to store the largest subsets that satisfy the condition for each element in `nums`.
4. Iterate over each element in `nums` with index `i`.
5. For each `i`, iterate over each element with index `j` that comes before `i`.
6. If `nums[i]` is divisible by `nums[j]` and the length of the subset at `dp[i]` is less than the length of the subset at `dp[j]` plus one, update `dp[i]` to be the subset at `dp[j]` plus `nums[i]`.
7. After iterating over all elements in `nums`, find and return the longest subset in `dp`.

Question

Solution

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