The problem is about simple interest and the principle of time value of money. The question states that Rs.2189 is divided into 3 parts such that their amounts after 1, 2 and 3 years may be equal respectively and interest being 4% in all cases. We need to find the smallest part.

Let's denote the three parts as P1, P2, and P3. According to the problem, the amounts after 1, 2, and 3 years are equal. This means:

P1 + P1*4/100*1 = P2 + P2*4/100*2 = P3 + P3*4/100*3

Solving these equations, we get:

P1 = P2/(1+0.04*2) = P3/(1+0.04*3)

Also, we know that P1 + P2 + P3 = 2189

Substituting P2 and P3 from the first equation into the second equation, we get:

P1 + P1*(1+0.04*2) + P1*(1+0.04*3) = 2189

Solving this equation, we get:

P1 = 2189 / (1 + 1.08 + 1.12) = Rs. 702

So, the smallest part is Rs. 702.

Question

The problem is about simple interest and the principle of time value of money. The question states that Rs.2189 is divided into 3 parts such that their amounts after 1, 2 and 3 years may be equal respectively and interest being 4% in all cases. We need to find the smallest part.

Let's denote the three parts as P1, P2, and P3. According to the problem, the amounts after 1, 2, and 3 years are equal. This means:

P1 + P1*4/100*1 = P2 + P2*4/100*2 = P3 + P3*4/100*3

Solving these equations, we get:

P1 = P2/(1+0.04*2) = P3/(1+0.04*3)

Also, we know that P1 + P2 + P3 = 2189

Substituting P2 and P3 from the first equation into the second equation, we get:

P1 + P1*(1+0.04*2) + P1*(1+0.04*3) = 2189

Solving this equation, we get:

P1 = 2189 / (1 + 1.08 + 1.12) = Rs. 702

So, the smallest part is Rs. 702.

Knowee AI · Accepted Answer

The problem is about simple interest and the principle of time value of money. The question states that Rs.2189 is divided into 3 parts such that their amounts after 1, 2 and 3 years may be equal respectively and interest being 4% in all cases. We need to find the smallest part.

Let's denote the three parts as P1, P2, and P3. According to the problem, the amounts after 1, 2, and 3 years are equal. This means:

P1 + P1*4/100*1 = P2 + P2*4/100*2 = P3 + P3*4/100*3

Solving these equations, we get:

P1 = P2/(1+0.04*2) = P3/(1+0.04*3)

Also, we know that P1 + P2 + P3 = 2189

Substituting P2 and P3 from the first equation into the second equation, we get:

P1 + P1*(1+0.04*2) + P1*(1+0.04*3) = 2189

Solving this equation, we get:

P1 = 2189 / (1 + 1.08 + 1.12) = Rs. 702

So, the smallest part is Rs. 702.

Rs.2189 is divided into 3 parts such that their amounts after 1, 2 and 3 years may be equal respectively and interest being 4% in all cases. The smallest part isMarks : 2Negative Marks : 0Answer hereRs.702Rs.597Rs.756Rs.1093

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