How many liters is 3.59 x 1019 atoms of argon gas at STP?

To solve this problem, we need to use Avogadro's Law which states that one mole of any gas at standard temperature and pressure (STP) occupies a volume of 22.4 liters.

1. First, we need to find out how many moles of argon gas are there in 3.59 x 10^19 atoms. We know that one mole of any substance contains Avogadro's number (6.022 x 10^23) of atoms. So, we can calculate the number of moles by dividing the number of atoms by Avogadro's number:

   Number of moles = 3.59 x 10^19 atoms / 6.022 x 10^23 atoms/mole = 0.0000596 moles

2. Then, we use Avogadro's Law to find out the volume of this amount of argon gas at STP. We multiply the number of moles by the volume of one mole of gas at STP:

   Volume = 0.0000596 moles * 22.4 liters/mole = 0.00134 liters

So, 3.59 x 10^19 atoms of argon gas at STP occupy a volume of approximately 0.00134 liters.