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What does the following Python code snippet do?class LinkedList:    def __init__(self):        self.head = None    def append(self, data):        new_node = Node(data)        if self.head is None:            self.head = new_node        else:            current = self.head            while current.next:                current = current.next            current.next = new_nodeDeletes the last node of the linked listInserts a new node at the beginning of the linked listInserts a new node at the end of the linked listReverses the linked list

Question

What does the following Python code snippet do?class LinkedList:    def init(self):        self.head = None    def append(self, data):        new_node = Node(data)        if self.head is None:            self.head = new_node        else:            current = self.head            while current.next:                current = current.next            current.next = new_nodeDeletes the last node of the linked listInserts a new node at the beginning of the linked listInserts a new node at the end of the linked listReverses the linked list

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Solution

The provided Python code snippet defines a simple LinkedList class. This class has two methods:

  1. __init__: This is the constructor method that is automatically called when an object of this class is created. It initializes the head of the LinkedList to None.

  2. append: This method is used to add a new node to the end of the LinkedList. It first creates a new node with the provided data. If the LinkedList is empty (i.e., the head is None), it sets the new node as the head. If the LinkedList is not empty, it traverses the LinkedList to find the last node and sets the next attribute of the last node to the new node.

So, the Python code snippet inserts a new node at the end of the LinkedList.

This problem has been solved

Similar Questions

What is the output of the following Python code snippet?class LinkedList:    def __init__(self):        self.head = None    def append(self, data):        new_node = Node(data)        if self.head is None:            self.head = new_node        else:            current = self.head            while current.next:                current = current.next            current.next = new_node    def display(self):        current = self.head        while current:            print(current.data, end=" ")            current = current.nextll = LinkedList()ll.append(1)ll.append(2)ll.display()

What will be the output of the following code?class Node:    def __init__(self, data=None):        self.data = data        self.next = Noneclass LinkedList:    def __init__(self):        self.head = None    def print_list(self):        current_node = self.head        while current_node:            print(current_node.data)            current_node = current_node.next    def insert_at_beginning(self, new_data):        new_node = Node(new_data)        new_node.next = self.head        self.head = new_nodellist = LinkedList()llist.insert_at_beginning(3)llist.insert_at_beginning(2)llist.insert_at_beginning(1)llist.print_list()Options1 2 31 3 22 3 13 2 1

What does the following Python code snippet accomplish?def reverse_linked_list(head):    prev = None    current = head    while current is not None:        next_node = current.next        current.next = prev        prev = current        current = next_node    head = prev    return head

What is the purpose of the append method in a linked list?Inserts a new node at the beginning of the linked listDeletes the last node of the linked listAppends a new node to the end of the linked listReverses the linked list

What does the following Python code snippet do?def delete_node(self, key):    temp = self.head    if temp is not None:        if temp.data == key:            self.head = temp.next            temp = None            return    while temp is not None:        if temp.data == key:            break        prev = temp        temp = temp.next    if temp == None:        return    prev.next = temp.next    temp = None

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