static double calculate( int num) { return num * 2 + 1;}public static void main( String[]args) { int x = 8; double result = calculate( x );}What is the value in result after this code is executed?
Question
static double calculate( int num) { return num * 2 + 1;}public static void main( String[]args) { int x = 8; double result = calculate( x );}What is the value in result after this code is executed?
Solution
The value in "result" after this code is executed is 17.0.
Here's the step by step explanation:
- The main method is called, which is the entry point of any Java program.
- Inside the main method, an integer variable 'x' is declared and initialized with the value 8.
- Then, a double variable 'result' is declared. It's value is set by calling the 'calculate' method with 'x' as the argument.
- Inside the 'calculate' method, the argument 'num' is multiplied by 2 and then 1 is added. Since 'num' is 8 (the value of 'x'), the calculation is 8 * 2 + 1, which equals 17.
- This value (17) is then returned from the 'calculate' method and assigned to the 'result' variable.
- Therefore, the value of 'result' after the code is executed is 17.0 (it's a double so it includes the decimal point).
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