To solve this problem, we can use the formula for the square of a binomial, which is (a + b)^2 = a^2 + 2ab + b^2.

Given that (b + c)^2 = 61, we can expand this to b^2 + 2bc + c^2 = 61.

We are also given that bc = 7.

We can substitute 2*7 for 2bc in the expanded equation, which gives us b^2 + 14 + c^2 = 61.

Subtract 14 from both sides to isolate b^2 + c^2, which gives us b^2 + c^2 = 61 - 14 = 47.

So, b^2 + c^2 = 47.

Therefore, the answer is (C) 47.

Question

To solve this problem, we can use the formula for the square of a binomial, which is (a + b)^2 = a^2 + 2ab + b^2.

Given that (b + c)^2 = 61, we can expand this to b^2 + 2bc + c^2 = 61.

We are also given that bc = 7.

We can substitute 2*7 for 2bc in the expanded equation, which gives us b^2 + 14 + c^2 = 61.

Subtract 14 from both sides to isolate b^2 + c^2, which gives us b^2 + c^2 = 61 - 14 = 47.

So, b^2 + c^2 = 47.

Therefore, the answer is (C) 47.

Knowee AI · Accepted Answer

To solve this problem, we can use the formula for the square of a binomial, which is (a + b)^2 = a^2 + 2ab + b^2.

Given that (b + c)^2 = 61, we can expand this to b^2 + 2bc + c^2 = 61.

We are also given that bc = 7.

We can substitute 2*7 for 2bc in the expanded equation, which gives us b^2 + 14 + c^2 = 61.

Subtract 14 from both sides to isolate b^2 + c^2, which gives us b^2 + c^2 = 61 - 14 = 47.

So, b^2 + c^2 = 47.

Therefore, the answer is (C) 47.

If b and c are positive, (b + c)2 = 61 and bc = 7, what is b2 + c2?(A) 9(B) 37(C) 47(D) 54(E) 68