The ground state energy of hydrogen atom is (–13.6 eV). Consider an electronic state Ψ of He+ whose energy, azimuthal quantum number and magnetic quantum number are (–6.04 eV); (2) and (0) respectively. Which of the following statement(s) is/are true for the state Ψ?It is a 3d stateIt has 2 angular nodesIt has no radial nodeIt is gerade orbital

The given state Ψ of He+ has an energy of -6.04 eV, azimuthal quantum number (l) of 2, and magnetic quantum number (m) of 0.

1. It is a 3d state: The azimuthal quantum number (l) determines the shape of the orbital and is associated with the angular momentum. For l=0, it's an s orbital; for l=1, it's a p orbital; for l=2, it's a d orbital; and for l=3, it's an f orbital. Since l=2 in this case, it is indeed a 3d state. So, this statement is true.

2. It has 2 angular nodes: The number of angular nodes is equal to the azimuthal quantum number (l). Since l=2, there are indeed 2 angular nodes. So, this statement is also true.

3. It has no radial node: The number of radial nodes is given by (n-l-1), where n is the principal quantum number. The energy of the state is -6.04 eV, which is half the ground state energy of hydrogen (-13.6 eV). This suggests that n=2 for this state (since the energy levels of hydrogen are given by -13.6/n^2 eV). Therefore, the number of radial nodes is (2-2-1) = -1, which is not possible. So, this statement is false.

4. It is a gerade orbital: The term "gerade" is used to describe orbitals with even symmetry, often in the context of molecular orbitals rather than atomic orbitals. In the case of atomic orbitals, s and d orbitals are usually considered "gerade". So, this statement could be considered true.

In conclusion, the statements "It is a 3d state", "It has 2 angular nodes", and "It is a gerade orbital" are true, while the statement "It has no radial node" is false.