(char)('a' + Math.random() * ('z' - 'a' + 1)) returns a random character ________.Group of answer choicesbetween 'a' and 'z'between 'a' and 'y'between 'b' and 'z'between 'b' and 'y'
Question
(char)('a' + Math.random() * ('z' - 'a' + 1)) returns a random character ________.Group of answer choicesbetween 'a' and 'z'between 'a' and 'y'between 'b' and 'z'between 'b' and 'y'
Solution
The expression (char)('a' + Math.random() * ('z' - 'a' + 1)) returns a random character between 'a' and 'z'.
Here's the step-by-step explanation:
-
'a'and'z'are characters, but in Java, characters can be used in arithmetic operations because they are implicitly cast to their ASCII values. The ASCII value of 'a' is 97 and 'z' is 122. -
Math.random()generates a random double value between 0.0 (inclusive) and 1.0 (exclusive). -
('z' - 'a' + 1)calculates the number of characters from 'a' to 'z', inclusive. The result is 26. -
Math.random() * ('z' - 'a' + 1)generates a random double value between 0.0 (inclusive) and 26.0 (exclusive). -
`'a'
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