Solve 2𝑥+8≤102x+8≤10 or 2𝑥+8>202x+8>20.
Question
Solve 2𝑥+8≤102x+8≤10 or 2𝑥+8>202x+8>20.
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Solution
Sure, let's solve these inequalities step by step.
First, let's solve 2x + 8 ≤ 10:
Step 1: Subtract 8 from both sides of the inequality: 2x ≤ 10 - 8 2x ≤ 2
Step 2: Divide both sides by 2: x ≤ 2/2 x ≤ 1
So, the solution to the first inequality is x ≤ 1.
Now, let's solve 2x + 8 > 20:
Step 1: Subtract 8 from both sides of the inequality: 2x > 20 - 8 2x > 12
Step 2: Divide both sides by 2: x > 12/2 x > 6
So, the solution to the second inequality is x > 6.
Therefore, the solution to the original problem is x ≤ 1 or x > 6.
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