Describe what the following function does line by line and the expected values for each line given its execution with the value x=3 until the end of its execution.def recursiveFunction(x):    if x<0:        return x    else:        return recursiveFunction(x-1)

This function is a recursive function, which means it calls itself within its own definition. Here's what it does line by line:

1. def recursiveFunction(x): This line defines the function recursiveFunction with one argument x.

2. if x<0: This line checks if x is less than 0.

3. return x If x is less than 0, the function returns x and stops executing.

4. else: If x is not less than 0, the function proceeds to the next line.

5. return recursiveFunction(x-1) This line calls the function itself with the argument x-1.

Given the execution with the value x=3, here's what happens:

1. In the first call, x is 3, which is not less than 0, so the function calls itself with x-1, which is 2.

2. In the second call, x is 2, which is not less than 0, so the function calls itself with x-1, which is 1.

3. In the third call, x is 1, which is not less than 0, so the function calls itself with x-1, which is 0.

4. In the fourth call, x is 0, which is not less than 0, so the function calls itself with x-1, which is -1.

5. In the fifth call, x is -1, which is less than 0, so the function returns x, which is -1.

So, the function returns -1 when called with x=3.

Please note that this function will result in a recursion error if called with a positive integer because it will keep calling itself indefinitely. It only stops when x is less than 0.