Solve: 1. A sample of tap water containing magnesium ions (Mg²⁺) is titrated with a 0.02 M EDTA solution. It takes 10.0 mL of the EDTA solution to titrate 50.0 mL of the water sample. Calculate the concentration of magnesium ions in the water sample. 3 marks 2. A 50.0 mL sample of wastewater is titrated with a 0.02 M EDTA solution to determine the concentration of magnesium ions (Mg²⁺). It requires 22.5 mL of the EDTA solution to reach the end point. Calculate the concentration of magnesium ions in the wastewater sample. 3 marks Problem: You are titrating a 50.0 mL solution of an unknown concentration of chloride ions (Cl⁻) with 0.100 M silver nitrate (AgNO₃) using a silver/silver chloride electrode. The standard electrode potential for the silver/silver chloride electrode is E∘=0.222 V. Calculate the potential of the solution at the following points:
Question
Solve:
- A sample of tap water containing magnesium ions (Mg²⁺) is titrated with a 0.02 M EDTA solution. It takes 10.0 mL of the EDTA solution to titrate 50.0 mL of the water sample. Calculate the concentration of magnesium ions in the water sample. 3 marks
- A 50.0 mL sample of wastewater is titrated with a 0.02 M EDTA solution to determine the concentration of magnesium ions (Mg²⁺). It requires 22.5 mL of the EDTA solution to reach the end point. Calculate the concentration of magnesium ions in the wastewater sample. 3 marks Problem: You are titrating a 50.0 mL solution of an unknown concentration of chloride ions (Cl⁻) with 0.100 M silver nitrate (AgNO₃) using a silver/silver chloride electrode. The standard electrode potential for the silver/silver chloride electrode is E∘=0.222 V. Calculate the potential of the solution at the following points:
Solution
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The concentration of magnesium ions in the water sample can be calculated using the formula:
C1V1 = C2V2
Where: C1 = concentration of EDTA solution = 0.02 M V1 = volume of EDTA solution = 10.0 mL = 0.01 L C2 = concentration of magnesium ions in the water sample (unknown) V2 = volume of water sample = 50.0 mL = 0.05 L
Solving for C2 gives:
C2 = (C1V1) / V2 C2 = (0.02 M * 0.01 L) / 0.05 L C2 = 0.004 M
Therefore, the concentration of magnesium ions in the water sample is 0.004 M.
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Similarly, the concentration of magnesium ions in the wastewater sample can be calculated using the same formula:
C1 = concentration of EDTA solution = 0.02 M V1 = volume of EDTA solution = 22.5 mL = 0.0225 L C2 = concentration of magnesium ions in the wastewater sample (unknown) V2 = volume of wastewater sample = 50.0 mL = 0.05 L
Solving for C2 gives:
C2 = (C1V1) / V2 C2 = (0.02 M * 0.0225 L) / 0.05 L C2 = 0.009 M
Therefore, the concentration of magnesium ions in the wastewater sample is 0.009 M.
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The potential of the solution at different points during the titration cannot be calculated without additional information, such as the initial concentration of chloride ions in the solution, the volume of silver nitrate solution added at each point, and the Nernst equation.
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