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A family plans to have 3 children. For each birth, assume that the probability of a boy is the same as the probability of a girl. What is the probability that they will have at least one boy and at least one girl?

Question

A family plans to have 3 children. For each birth, assume that the probability of a boy is the same as the probability of a girl. What is the probability that they will have at least one boy and at least one girl?

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Solution

To solve this problem, we can use the concept of probability.

Step 1: Calculate the total number of outcomes The total number of outcomes when a family has 3 children can be calculated as 2^3 = 8. This is because each child can be either a boy or a girl, and there are 3 children. So, the total outcomes are: BBB, BBG, BGB, BGG, GBB, GBG, GGB, GGG.

Step 2: Calculate the number of favorable outcomes The favorable outcomes are the ones where the family has at least one boy and one girl. So, we exclude the outcomes where all are boys (BBB) and all are girls (GGG). This leaves us with 6 favorable outcomes: BBG, BGB, BGG, GBB, GBG, GGB.

Step 3: Calculate the probability The probability of an event is calculated as the number of favorable outcomes divided by the total number of outcomes. So, the probability that the family will have at least one boy and one girl is 6/8 = 0.75 or 75%.

This problem has been solved

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