A body of 5kg is moving with a velocity of 20m/s. If a force of 100N is applied on it for 10sec in the same direction as its velocity, what will now be the velocity of body?
Question
A body of 5kg is moving with a velocity of 20m/s. If a force of 100N is applied on it for 10sec in the same direction as its velocity, what will now be the velocity of body?
Solution
To solve this problem, we need to use Newton's second law of motion, which states that the force applied on an object is equal to the change in its momentum (mass times velocity) over time. This can be written as:
F = m * a
where: F is the force, m is the mass of the object, and a is the acceleration of the object.
First, we need to find the acceleration of the body. We can rearrange the formula to solve for a:
a = F / m
Substituting the given values:
a = 100N / 5kg = 20m/s²
This is the acceleration of the body.
Next, we use the formula for acceleration, which is the change in velocity over time:
a = Δv / t
where: Δv is the change in velocity, and t is the time.
We can rearrange this formula to solve for Δv:
Δv = a * t
Substituting the values we have:
Δv = 20m/s² * 10s = 200m/s
This is the change in velocity.
Finally, we add this change in velocity to the initial velocity to find the final velocity:
v_final = v_initial + Δv
Substituting the values we have:
v_final = 20m/s + 200m/s = 220m/s
So, the final velocity of the body is 220m/s.
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