In how many ways 5 boys sit round the table, so that two particular boys are next to each other?Options42124824

To solve this problem, we can use the concept of permutations in combinatorics. Here are the steps:

1. Consider the two particular boys as a single entity. So now we have 4 entities to arrange (3 boys + 1 entity of 2 boys).

2. Since they are sitting in a round table, the number of arrangements is (n-1)!. So, the number of ways these 4 entities can be arranged is (4-1)!= 3! = 321 = 6 ways.

3. However, the two particular boys (considered as a single entity) can switch places with each other. So, there are 2! = 2 ways for them to sit.

4. Therefore, the total number of ways the 5 boys can sit around the table so that the two particular boys are next to each other is 6*2 = 12 ways.

So, the correct answer is 12.