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(c) A prize wheel has 8 fields of different sizes that are numbered 1, 2, 3, 4, 5, 6, 7 and 8. The probabilities for the following events are known: 𝑃({8,1,3,7})=913 and 𝑃({8,2,4,5,6})=713.Find 𝑃({8})=? (Enter as a reduced fraction).

Question

(c) A prize wheel has 8 fields of different sizes that are numbered 1, 2, 3, 4, 5, 6, 7 and 8. The probabilities for the following events are known: 𝑃({8,1,3,7})=913 and 𝑃({8,2,4,5,6})=713.Find 𝑃({8})=? (Enter as a reduced fraction).

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Solution

To find the probability of event {8}, we can use the given probabilities of the two events that include 8: {8,1,3,7} and {8,2,4,5,6}.

The sum of these two probabilities is equal to the total probability of all events, which is 1.

So, we have:

𝑃({8,1,3,7}) + 𝑃({8,2,4,5,6}) = 1

Substituting the given values:

9/13 + 7/13 = 1

16/13 = 1

This is not possible, as the total probability cannot exceed 1.

There seems to be a mistake in the given probabilities. Please check the values and try again.

This problem has been solved

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