A single mode fiber has a beat length of 4cm at 1200nm. What is birefringence?a.3*(10^-5)b.2*(10^-5)c.2d.1.2*(10^-5)
Question
A single mode fiber has a beat length of 4cm at 1200nm. What is birefringence?a.3*(10^-5)b.2*(10^-5)c.2d.1.2*(10^-5)
Solution
The birefringence of a fiber can be calculated using the formula:
Birefringence = Wavelength / Beat length
Given in the problem, the wavelength (λ) is 1200nm or 1200 * 10^-9 m and the beat length is 4cm or 0.04m.
So, Birefringence = (1200 * 10^-9 m) / 0.04 m = 3 * 10^-5
So, the answer is a. 3*(10^-5).
Similar Questions
A single mode fiber has mode field diameter 10.2μm and V=2.20. What is the core diameter of this fiber?a.7.6μmb.10.1μmc.11.1μmd.13.2μm
Consider a single mode fiber having core refractive index n1= 1.5. The fiber length is 12m. Find the time taken by the axial ray to travel along the fiber.a.0.06μsecb.0.30μsecc.0.90μsecd.1.00μsec
A 20 cm long organ pipe is filled with air and is open at one end and closed at the other. The speed of sound in air at 0°C is 331 m/s. What is the wavelength of the fundamental mode?
as radius of fiber increases the number of modes ________
Dispersion-shifted single mode fibers are created by __________a.Decreasing fiber core diameter and decreasing fractional index differenceb.Decreasing fiber core diameter and increasing fractional index differencec.Increasing fiber core diameter and increasing fractional index differenced.Increasing fiber core diameter and decreasing fractional index difference
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.