To solve this problem, we first need to find the current flowing through the lamp. We can use Ohm's law for this, which states that the current is equal to the power divided by the voltage.

So, the current I = P/V = 60W / 110V = 0.545 A.

Now, we know that the lamp is connected in series with the capacitor to a 220V AC mains. In a series circuit, the current flowing through each component is the same. So, the current flowing through the capacitor is also 0.545 A.

The voltage across the capacitor can be found using the formula V = I * Xc, where Xc is the capacitive reactance. However, we don't have the value of Xc.

Without the value of the capacitor or the frequency of the AC mains, we can't calculate the voltage across the capacitor. We need more information to solve this problem.

Question

To solve this problem, we first need to find the current flowing through the lamp. We can use Ohm's law for this, which states that the current is equal to the power divided by the voltage.

So, the current I = P/V = 60W / 110V = 0.545 A.

Now, we know that the lamp is connected in series with the capacitor to a 220V AC mains. In a series circuit, the current flowing through each component is the same. So, the current flowing through the capacitor is also 0.545 A.

The voltage across the capacitor can be found using the formula V = I * Xc, where Xc is the capacitive reactance. However, we don't have the value of Xc.

Without the value of the capacitor or the frequency of the AC mains, we can't calculate the voltage across the capacitor. We need more information to solve this problem.

Knowee AI · Accepted Answer

To solve this problem, we first need to find the current flowing through the lamp. We can use Ohm's law for this, which states that the current is equal to the power divided by the voltage.

So, the current I = P/V = 60W / 110V = 0.545 A.

Now, we know that the lamp is connected in series with the capacitor to a 220V AC mains. In a series circuit, the current flowing through each component is the same. So, the current flowing through the capacitor is also 0.545 A.

The voltage across the capacitor can be found using the formula V = I * Xc, where Xc is the capacitive reactance. However, we don't have the value of Xc.

Without the value of the capacitor or the frequency of the AC mains, we can't calculate the voltage across the capacitor. We need more information to solve this problem.

A 110 V, 60 W lamp is run from a 220 V AC mains using a capacitor in series withe the lamp, instead of a resistor then the voltage across the capacitor is about:

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