NumberFormatExceptionAnother typical exception that you have probably already encountered is when using a BufferedReader to read input. You must parse the string into different data types, such as integer and double. A NumberFormatException is thrown, for instance, if you attempt to parse a string ("abc") into an integer. In order to handle this NumberFormat error, let's try This issue might arise in our program when getting properties for classes like ItemType. then attempt to control it in this program.Create a class ItemType with the following attribute: "Add appropriate getter and setter, default, and parameterized constructor." public ItemType(String name, Double deposit, Double costPerDay). Override toString() and print the details.Input format :The first line of the input consists of the name.The second line of the input consists of the deposit.The third line of the input consists of the cost per day.Output format :The output prints the item details or the exception details.Refer to the sample input and output for format specifications.Sample test cases :Input 1 :Electronics1000100Output 1 :Electronics 1000.0 100.0Input 2 :Electronicsone thousandOutput 2 :java.lang.NumberFormatException: For input string: "one thousand"

An attempt to convert string to a number type uses which of the following exception? Example- String s=”xyz” int i=Integer.parseInt(s);a) NumberFormatExceptionc) ArrayIndexOutOfBoundd) NullPointerb) AirthmeticException

Which exception would occur if the program is expecting an integer but a String is passed in?You did not enter a valid integerInputMismatchExceptionIntExpectedExceptionnextInt

public class Hello{ public static void main(String args[]) { int num = 190; String rev_num = " " ; while (num!=0){ int digit = num%10; rev_num = rev_num+digit; num = num /= 10 ; } System.out.println((Integer.parseInt(rev_num)));} } Exception in thread "main" java.lang.NumberFormatException: For input string: " 091" at java.base/java.lang.NumberFormatException.forInputString(NumberFormatException.java:67) at java.base/java.lang.Integer.parseInt(Integer.java:654) at java.base/java.lang.Integer.parseInt(Integer.java:786)

public class Main { public static void main(String args[]) {                       blank        }}Drag and drop the correct code which will cause NumberFormatException when the above code is compiled.int x = Integer.parseInt("5.6"); double pi=Double.parseDouble("3.14");  boolean status=Boolean.parseBoolean("TRUE");

1.Data Type Exception Get an integer input, If the input is 1, Throw an Integer exception. If the input is 2, Throw a Character exception. If the input is 3, Throw a double exception. Input Format The input consists of an integer. Output Format The output prints the corresponding exception. Refer sample output for formatting exception. Sample Input 1 Sample Output Integer exception caught. Sample Input 2 Sample Output Character exception caught. Sample Input 3 Sample Output Double exception caught.