The liquid fills a space between two parallel plates, 1.4 cm apart.What force is required to move one plate past the other stationary plate with a velocity of 3.47 cm/s, if the moving plate has an area of 3.8 m2?Give your answer in Newtons unit.Viscosity is 5.13x 10-3 Pa.s
Question
The liquid fills a space between two parallel plates, 1.4 cm apart.What force is required to move one plate past the other stationary plate with a velocity of 3.47 cm/s, if the moving plate has an area of 3.8 m2?Give your answer in Newtons unit.Viscosity is 5.13x 10-3 Pa.s
Solution
The force required to move one plate past the other can be calculated using the formula for viscous force:
F = η * A * (v / d)
where: F is the force, η is the viscosity, A is the area, v is the velocity, and d is the distance between the plates.
Given: η = 5.13 x 10^-3 Pa.s, A = 3.8 m^2, v = 3.47 cm/s = 0.0347 m/s (since 1 m = 100 cm), and d = 1.4 cm = 0.014 m.
Substituting these values into the formula, we get:
F = (5.13 x 10^-3 Pa.s) * (3.8 m^2) * (0.0347 m/s / 0.014 m)
After calculating the above expression, we get the force F in Newtons.
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